Calculate the volume of carbon monoxide (IV) formed during the combustion of 2 liters of butane.

Butane is a gaseous saturated hydrocarbon with the formula C4H10.

Let’s write the equation of combustion of butane in oxygen and arrange the coefficients:

2C4H10 + 3O2 = 8CO2 + 10H2O.

Since all reagents and CO2 are gases, it makes no sense to go over to the amount of a mole of a substance (the molar volume of gases at a given temperature is the same).

Based on the reaction equation: from 2 moles of butane, 8 moles of carbon dioxide are obtained (4 times more).

According to the condition of the problem, the volume of butane (2 l) that reacts is known. This means that 2 liters of butane will make 8 liters of carbon dioxide.