Calculate the volume of carbon monoxide (IV) formed during the decomposition of 50 g of calcium

Calculate the volume of carbon monoxide (IV) formed during the decomposition of 50 g of calcium carbonate. CaCO3 = CaO + CO2

CaCO3 = CaO + CO2
The molar mass of calcium carbotate is 100 g / mol, which means it has entered into a reaction: 50 g: 100 g / mol = 0.5 mol. The same amount of carbon dioxide was obtained, the volume of which will be: 0.5 mol * 22.4 l / mol = 11.2 l.



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