Calculate the volume of carbon monoxide (IV) obtained by reacting acetic acid with 60 g of limestone

| September 24, 2021 | education

Calculate the volume of carbon monoxide (IV) obtained by reacting acetic acid with 60 g of limestone (calcium carbonate), in which there are 10% impurities?

1. Let’s compose the equation of the chemical reaction:

CaCO3 + 2CH3COOH = (CH3COO) 2Ca + CO2 + H2O.

2. Find the chemical amount of calcium carbonate:

ω (CaCO3) = 100% – ω (impurities) = 100% – 10% = 90%.

m (CaCO3) = m (mixtures) * ω (CaCO3) / 100% = 60 g * 90% / 100% = 54 g.

n (CaCO3) = m (CaCO3) / M (CaCO3) = 54 g / 100 g / mol = 0.54 mol.

3. According to the reaction equation, we find the chemical amount of carbon monoxide, and then its volume (Vm – molar volume, constant equal to 22.4 l / mol):

n (CO2) = n (CaCO3) = 0.54 mol.

V (CO2) = n (CO2) * Vm = 0.54 mol * 22.4 l / mol = 12.1 l.

Answer: V (CO2) = 12.1 liters.



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