Calculate the volume of carbon monoxide (IV) that can be absorbed by calcium hydroxide, weighing 80 g

| March 4, 2021 | education

Calculate the volume of carbon monoxide (IV) that can be absorbed by calcium hydroxide, weighing 80 g, containing 0.08 mass fraction of impurities.

Let us express the mass fraction of impurities as a percentage.

0.08 × 100 = 8%.

Let’s find the mass of pure calcium hydroxide without impurities.

100% – 8% = 92%.

80g – 100%,

x – 92%,

x = (80 g × 92%): 100% = 73.6 g.

Find the amount of calcium hydroxide substance.

n = m: M.

M (Ca (OH) 2) = 40 + 34 = 74 g / mol.

n = 73.6 g: 74 g / mol = 0.99 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

Ca (OH) 2 + CO2 = CaCO3 + H2O.

1 mole of calcium hydroxide accounts for 1 mole of carbon dioxide. The substances are in quantitative ratios of 1: 1. The amount of the substance will be the same.

n (Ca (OH) 2) = n (CO2) = 0.99 mol.

Let’s find the volume of carbon dioxide.

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

V = 22.4 L / mol × 0.99 mol = 22.176 L.

Answer: V = 22.176 liters.



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