Calculate the volume of carbon monoxide (IV) that can be obtained from 500 g of calcium carbonate.
May 25, 2021 | education
| The decomposition reaction of calcium carbonate is described by the following chemical equation:
Na2CO3 = Na2O + CO2;
One mole of calcium carbonate forms one mole of carbon dioxide.
Let’s determine the molar amount of a substance in 500 grams of calcium carbonate.
To do this, first determine its molar mass:
M Na2CO3 = 23 x 2 + 12 + 16 x 3 = 106 grams / mol;
The amount of the substance will be:
N Na2CO3 = 500/106 = 4.717 mol;
Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.
Let us determine the volume of 4.717 mol of carbon dioxide:
V Na2CO3 = 4.717 x 22.4 = 105.66 liters;
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