Calculate the volume of carbon monoxide (IV) that can be obtained from the decomposition

Calculate the volume of carbon monoxide (IV) that can be obtained from the decomposition of calcium carbonate weighing 720 g, the mass fraction of impurities in which is 8%.

Given:
m mixture (CaCO3) = 720 g
w approx (CaCO3) = 8%
To find:
V (CO2)
Decision:
CaCO3 = CaO + CO2
w is clean. islands (CaCO3) = 100% -8% = 92% = 0.92
m in islands (CaCO3) = m mixture * w pure. in-va = 720 g * 0.92 = 662.4 g
n (CaCO3) = m / M = 662.4 g / 100 g = mol = 6.624 mol
n (CaCO3): n (CO2) = 1: 1
n (CO2) = 6.624 mol
V (CO2) = n * Vm = 6.624 mol * 22.4 l / mol = 148 l
Answer: 148 l