Calculate the volume of chlorine required to obtain 320 g pure bromine from potassium bromide?

Given:
m (Br2) = 320 g
To find:
V (Cl2) =?
Decision:
1) We draw up the equation of the chemical reaction, let the volume of chlorine be x l.
2KBr + Cl2 = 2KCl + Br2
2) Find the molecular weight of bromine.
M (Br2) = 80 g / mol x 2 = 160 g / mol
3) Find the molar volume of chlorine.
Vm (Cl2) = 22.4 L / mol
4) x L: 22.4 L / mol = 320 g: 160 g / mol
x = (22.4 x 320): 160 = 44.8 liters.
Answer: V (Cl2) = 44.8 liters.