Calculate the volume of chlorine that will be required to displace all the iodine from 300g

Calculate the volume of chlorine that will be required to displace all the iodine from 300g of a 15% potassium iodide solution. Calculate the amount of new salt substance that is formed.

1. Let’s compose the equation of the chemical reaction:

2KI + Cl2 = 2KCl + I2.

2. Find the chemical amount of potassium iodide:

m (KI) = m (solution) * ω (KI) / 100% = 300 g * 15% / 100% = 45 g.

n (KI) = m (KI) / M (KI) = 45 g / 166 g / mol = 0.27 mol.

3. According to the reaction equation, we find the amount of potassium chloride; chlorine, and its deputy volume (Vm – molar volume, constant equal to 22.4 l / mol):

n (KCl) = n (KI) = 0.27 mol.

n (Cl2) = n (KI) / 2 = 0.27 mol / 2 = 0.136 mol.

V (Cl2) = n (Cl2) * Vm = 0.136 mol * 22.4 L / mol = 3.04 L.

Answer: n (KCl) = 0.27 mol; V (Cl2) = 3.04 l.



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