Calculate the volume of CO2 that will be released during the decomposition of marble m = 6.25 g

Calculate the volume of CO2 that will be released during the decomposition of marble m = 6.25 g, the mass fraction of calcium carbonate in marble is 80%.

The decomposition reaction of calcium carbonate when heated is described by the following chemical equation:

CaCO3 = CaO + CO2 ↑;

Let’s determine the chemical amount of calcium carbonate. To do this, we divide its weight by the mass of 1 mole of the substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 6.25 x 0.8 / 100 = 0.05 mol;

The same molar amount of carbon dioxide would theoretically be synthesized.

To calculate its volume, you need to multiply the amount of substance by the volume of 1 mole of gas (filling volume 22.4 liters).

V CO2 = 0.05 x 22.4 = 1.12 liters;