# Calculate the volume of ethylene released during dehydration of 100 g of ethyl alcohol if the mass

Calculate the volume of ethylene released during dehydration of 100 g of ethyl alcohol if the mass fraction of ethylene yield is 84%.

According to the condition of the problem, we write down the reaction equation:
С2Н5ОН = Н2О + С2Н4 – dehydration reaction, ethylene was obtained;
Let’s make calculations using the formulas:
M (C2H5OH) = 2 * 12 + 1 * 6 + 16 = 46 g / mol;
M (C2H4) = 2 * 12 + 1 * 4 = 28 g / mol;
Determine the amount of ethanol mol by the formula:
Y (C2H5OH) = m / M = 100/46 = 2.17 mol;
We compose the proportion using these equations:
2.17 mol (C2H5OH) – X mol (C2H4);
-1 mol -1 mol hence, X mol (C2H4) = 2.17 * 1/1 = 2.17 mol;
Determine the theoretical volume of ethylene:
V (C2H4) = 2.17 * 22.4 = 48.69 L;
Mass fraction of ethylene yield is 84% ​​= 0.84;
0.84 = V (practical) / V (theoretical);
V (practical) = 0.84 * 48.69 = 40.89 liters.
Answer: the practical yield of ethylene in the volume is 40.89 liters.

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