# Calculate the volume of ethylene released during dehydration of 100 g of ethyl alcohol if the mass

**Calculate the volume of ethylene released during dehydration of 100 g of ethyl alcohol if the mass fraction of ethylene yield is 84%.**

According to the condition of the problem, we write down the reaction equation:

С2Н5ОН = Н2О + С2Н4 – dehydration reaction, ethylene was obtained;

Let’s make calculations using the formulas:

M (C2H5OH) = 2 * 12 + 1 * 6 + 16 = 46 g / mol;

M (C2H4) = 2 * 12 + 1 * 4 = 28 g / mol;

Determine the amount of ethanol mol by the formula:

Y (C2H5OH) = m / M = 100/46 = 2.17 mol;

We compose the proportion using these equations:

2.17 mol (C2H5OH) – X mol (C2H4);

-1 mol -1 mol hence, X mol (C2H4) = 2.17 * 1/1 = 2.17 mol;

Determine the theoretical volume of ethylene:

V (C2H4) = 2.17 * 22.4 = 48.69 L;

Mass fraction of ethylene yield is 84% = 0.84;

0.84 = V (practical) / V (theoretical);

V (practical) = 0.84 * 48.69 = 40.89 liters.

Answer: the practical yield of ethylene in the volume is 40.89 liters.