Calculate the volume of ethylene that can be obtained from 23 g of ethanol if the volume fraction

Calculate the volume of ethylene that can be obtained from 23 g of ethanol if the volume fraction of the reaction product yield is 60% of the theoretically possible?

1. Ethylene can be obtained from ethanol by a dehydration reaction in the presence of acids.

C2H5OH = CH2 = CH2 + H2O

2. The amount of ethanol substance is found by the formula v = m / Mr, where m is the mass of the substance, v is the amount of the substance, Mr is the molecular weight.

Mr (C2H5OH) = 46 g / mol

v = 23/46 = 0.5 mol

3. Ethanol and ethylene are in a 1: 1 ratio, the amount of ethanol is equal to the amount of ethylene.

v (C2H5OH) = (C2H4) = 0.5 mol

4. The volume of ethylene is sought by the formula V = v * 22.4, where V is the volume of the substance, 22.4 l / mol is the molar volume of gases.

V (C2H4) = 0.5 * 22.4 = 11.2 L – theoretical yield, 100%

To find 60% of theoretical yield:

11.2 * 0.6 = 6.72 l

Answer: the volume of ethylene is 6.72 liters (60% yield).



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