Calculate the volume of ethylene that can be obtained from 23 g of ethanol if the volume

Calculate the volume of ethylene that can be obtained from 23 g of ethanol if the volume fraction of the product yield is 60% of the theoretical possibility.

Given:

Ɣ = 60%,

m (ethanol) = 23 g.

V (C2H4) -?

Decision:

Let’s find the amount of ethanol substance by the formula:

n = m: M.

M (C2H5OH) = 12 × 2 + 6 + 16 = 46 g / mol.

n = 23 g: 46 g / mol = 0.5 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

С2Н5ОН → Н2С = СН2 + H2O.

According to the reaction equation, there is 1 mole of ethylene per mole of ethanol. The substances are in quantitative ratios of 1: 1.

The amount of substance will be the same.

n (C2H5OH) = n (C2H4) = 0.5 mol.

Let’s find the volume of ethylene by the formula:

V = Vn n, where Vn is the molar volume of gas equal to 22.4 l / mol, and n is the amount of substance.

V = 22.4 L / mol × 0.5 mol = 11.2 L.

11.2 liters should be obtained according to theory. According to the problem statement, the ethylene yield was 60%.

Let’s find a practical way out of ethylene from the theoretically possible.

11.2 – 100%,

V – 60%,

V = (60% x 11.2): 100%,

V = 6.72 liters.

Or you can find a practical way out using the formula.

Ɣ = (Vpractical: Vtheoretic) × 100%.

Hence Vpractical = (Ɣ × Vtheoretic): 100%.

V practical = (11.2 l × 60%): 100% = 6.72 l.

Answer: 6.72 liters.