Calculate the volume of gas formed when the sulfuric acid solution interacts with 168 g of 10% sodium bicarbonate solution.

| March 7, 2021 | education

1.Let’s find the mass of sodium bicarbonate in the solution.

W = m (substance): m (solution) × 100%,

hence m (substance) = (m (solution) × w): 100%.

m (substance) = (168 g × 10%): 100% = 16.8 g.

2.Let’s find the amount of salt substance by the formula:

n = m: M.

M (NaHCO3) = 23 + 1 + 12 + 16 × 3 = 84 g / mol.

n = 16.8 g: 84 g / mol = 0.2 mol.

3. Let’s compose the equation of the reaction between sulfuric acid and sodium bicarbonate.

H2SO4 + 2NaHCO3 = Na2SO4 +2 CO2 + 2H2O.

4. Let’s find the quantitative ratios of substances.

2 mol of bicarbonate accounts for 2 mol of carbon dioxide.

So the amount of carbon monoxide substance and the amount of sodium bicarbonate substance are equal.

n (CO2) = 0.2 mol.

5. Let’s find the volume of carbon dioxide.

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

V = 22.4 L / mol × 0.2 mol = 4.48 L.

Answer: 4.48 liters.



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