Calculate the volume of gas released as a result of the interaction of magnesium with 146 g of HCL with a mass fraction of 20%.

1. Let’s find the mass of hydrochloric acid in solution, according to the formula:

m (HCl) = m (solution) * w (solution) / 100% = 146 g * 20% / 100% = 29.2 g

2. Let’s compose the equation of interaction of hydrochloric acid with magnesium:

Mg + 2 HCl = MgCl2 + H2

According to the equation:

consumed 2 mol of HCl;
gas H2 formed in the amount of 1 mol of substance, i.e. 22.4 l.
Let’s find the mass of HCl by the formula:

m (HCl) = n * M = 2 mol * (1 + 35.5) = 73 g

3. Let’s calculate the volume of H2, making the proportion:

29.2 g HCl – xl H2

73 g HCl – 22.4 L H2

Hence, x = 29.2 * 22.4 / 73 = 8.96 liters.