Calculate the volume of gas that forms when sodium carbonate reacts with 100 g of 20% hydrochloric acid solution.

The reaction of dissolving sodium carbonate in hydrochloric acid is described by the following chemical reaction equation:

Na2CO3 + 2HCl = 2NaCl + CO2 + H2O;

When 1 mol of sodium carbonate is dissolved in acid, 1 mol of gaseous carbon dioxide is synthesized. This consumes 2 mol of hydrochloric acid.

Let’s calculate the available chemical amount of hydrochloric acid substance.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 100 x 0.2 / 36.5 = 0.548 mol;

Thus, taking into account the yield of 100% when dissolving 0.548 / 2 = 0.274 mol of soda, 0.274 mol of carbon dioxide is synthesized.

Let’s calculate its volume. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 0.274 x 22.4 = 6.138 liters;



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