Calculate the volume of gas that forms when zinc reacts with 250 g of 10% hydrochloric acid solution.

Zinc metal reacts with hydrochloric (hydrochloric) acid to release hydrogen gas and form zinc chloride. The reaction is described by the following equation:

Zn + 2HCl = ZnCl2 + H2;

1 mole of metal reacts with 2 moles of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.

Let’s calculate the available chemical amount of acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 250 x 0.1 / 36.5 = 0.685 mol;

Half the amount of hydrogen will be synthesized. Let’s calculate its volume.

To do this, we divide its volume by the volume of 1 mole of ideal gas, which is 22.4 liters.

N H2 = 0.685 / 2 = 0.343 mol;

V H2 = 0.343 x 22.4 = 7.683 liters;