Calculate the volume of gas that is formed as a result of the interaction of 20 g of sodium carbonate

Calculate the volume of gas that is formed as a result of the interaction of 20 g of sodium carbonate with hydrochloric acid.

1. Let’s compose the equation of the chemical reaction:

Na2CO3 + 2 HCl = 2 NaCl + CO2 + H2O

As a result of the reaction, carbon dioxide is formed – CO2

According to the equation, sodium carbonate and carbon dioxide are taken in an amount of 1 mol.

Let’s find the mass of Na2CO3 by the formula:

m (Na2CO3) = n * M = 1 mol * (23 * 2 + 12 + 16 * 3) = 106 g

Let’s find the volume of CO2 using the formula:

V (CO2) = Vm * n = 22.4 L / mol * 1 mol = 22.4 L

2. Let’s calculate the volume of carbon dioxide, making up the proportion:

20 g Na2CO3 – xl CO2

106 g Na2CO3 – 22.4 l CO2

Hence, x = 20 * 22.4 / 106 = 4.2 liters.