Calculate the volume of gas that is released during the interaction of aminoethanic acid weighing 15 g

| August 11, 2021 | education

Calculate the volume of gas that is released during the interaction of aminoethanic acid weighing 15 g with sodium carbonate.

To solve, we write the equation:
1. 2NH2 – CH2 – COOH + Na2CO3 = 2NH2 – CH2 – COONa + CO2 + H2O – ion exchange reaction, carbon dioxide is released;
2. Let’s calculate the molar masses:
M (aminoox to-you) = 75 g / mol;
M (CO2) = 44 g / mol.
3. Determine the amount of moles of glycine (aminoacetic acid), if the mass is known:
Y = m / M = 15/75 = 0.2 mol.
4. According to the equation, we compose the proportion:
0.2 mol glycine – X mol (CO2);
-2 mol – 1 mol from here, X mol (CO2) = 0.2 * 1/2 = 0.1 mol.
5. Find the volume of carbon monoxide (4):
V (CO2) = 0.1 * 22.4 = 2.24 l.
Answer: during the reaction, carbon dioxide is released in a volume of 2.24 liters.



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