Calculate the volume of gas that is released when zinc reacts with 20% hydrochloric acid, 230 mg.

1. The interaction of zinc with hydrochloric acid proceeds according to the equation:

Zn + 2HCl = ZnCl2 + H2 ↑;

2. find the mass of hydrogen chloride:

m (HCl) = w (HCl) * m (solution);

m (HCl) = 0.2 * 0.23 = 0.046 g;

3. define the chemical amount:

n (HCl) = m (HCl): M (HCl) = 0.046: 36.5 = 0.0013 mol;

4.the chemical amount of hydrogen:

n (H2) = n (HCl): 2 = 0.0013: 2 = 0.00065 mol;

5. find the volume of gas:

V (H2) = n (H2) * Vm = 0.00065 * 22.4 = 0.01456 dm3 = 14.56 cm3.

Answer: 14.56 cm3.