Calculate the volume of gas that will be released when aluminum weighing 2.7 g

| April 29, 2021 | education

Calculate the volume of gas that will be released when aluminum weighing 2.7 g interacts with a 40% potassium hydroxide solution weighing 50 g.

1. Let’s compose the equation of a chemical reaction.

2Al + 2KOH + 6H2O = 2K [Al (OH) 4] + 3H2.

2. Find the amount of aluminum and potassium hydroxide.

n (Al) = m (Al) / M (Al) = 2.7 g / 27 g / mol = 0.1 mol.

m (KOH) = m (solution) * ω (KOH) / 100% = 50 g * 40% / 100% = 20 g.

n (KOH) = m (KOH) / M (KOH) = 20 g / 56 g / mol = 0.357 mol.

Aluminum is in short supply, therefore we will decide based on its quantity.

3. Using the reaction equation, we find the amount and then the volume of hydrogen.

n (H2) = n (Al) * 1.5 = 0.1 mol * 1.5 = 0.15 mol.

V (H2) = n (H2) * Vm = 0.15 mol * 22.4 L / mol = 3.36 L.

Answer: V (H2) = 3.36 liters.



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