Calculate the volume of gas that will be released when an excess of iron sulfide 2 acts on 490 grams of a 10

Calculate the volume of gas that will be released when an excess of iron sulfide 2 acts on 490 grams of a 10 percent sulfuric acid solution.

Given:
m solution (H2SO4) = 490 g
ω (H2SO4) = 10%

To find:
V (gas) -?

1) Write the reaction equation:
FeS + H2SO4 => H2S ↑ + FeSO4;
2) Calculate the mass of H2SO4:
m (H2SO4) = ω (H2SO4) * m solution (H2SO4) / 100% = 10% * 490/100% = 49 g;
3) Calculate the amount of substance H2SO4:
n (H2SO4) = m (H2SO4) / M (H2SO4) = 49/98 = 0.5 mol;
4) Determine the amount of substance H2S:
n (H2S) = n (H2SO4) = 0.5 mol;
5) Calculate the volume of H2S:
V (H2S) = n (H2S) * Vm = 0.5 * 22.4 = 11.2 liters.

Answer: The volume of H2S is 11.2 liters.