Calculate the volume of hydrogen and the mass of sulfur required to form 85g of hydrogen sulfide.

n – mole (nu, amount of substance). n = m / Mr; m = n × Mr; V = n × Vm (Vm = 22.4 (L / mol)).
Given: m (H2S) = 85g.
H2 + S = H2S.
1) n (H2S) = 85g / 2 + 32 = 85g / 34 (g / mol) = 2.5mol
2) n (H2S) = n (S) = 2.5 mol
m (S) = 2.5 mol × 32 (g / mol) = 80g.
3) n (H2S) = n (H2) = 2.5 mol.
V (H2) = 2.5 mol × 22.4 (L / mol) = 56 L
Answer: m (S) = 80g; V (H2) = 56l.



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