Calculate the volume of hydrogen at normal temperature, which will be released if 6.3 g

Calculate the volume of hydrogen at normal temperature, which will be released if 6.3 g of hydrochloric acid has entered the reaction with aluminum.

Aluminum reacts with hydrochloric acid. This forms an aluminum chloride salt and releases hydrogen gas. The interaction is described by the following chemical equation.

Al + 3HCl = AlCl3 + 3/2 H2;

Let’s find the chemical amount of hydrochloric acid. For this purpose, we divide its weight by the weight of 1 mole of acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 6.3 / 36.5 = 0.1726 mol;

The chemical amount of released hydrogen will be 2 times less: 0.1726 / 2 = 0.0863 mol

Let’s calculate its volume.

To do this, multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

V H2 = 0.0863 x 22.4 = 1.933 liters;

The weight of hydrogen will be:

M H2 = 2 grams / mol;

m H2 = 2 x 0.0863 = 0.1726 grams;