Calculate the volume of hydrogen chloride obtained by reacting 127 g of sodium chloride with sulfuric acid.

Given:
m (NaCl) = 127 g
To find:
V (HCl)
Decision:
2NaCl + H2SO4 = 2HCl + Na2SO4
n (NaCl) = m / M = 127 g / 58.5 g / mol = 2.17 mol
n (NaCl): n (HCl) = 1: 1
n (HCl) = 2.17 mol
V (HCl) = n * Vm = 2.17 mol * 22.4 L / mol = 48.61 L
Answer: 48, 61 l



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