Calculate the volume of hydrogen chloride required to neutralize a solution containing 33.6 grams of potassium hydroxide.

In accordance with the condition of the problem, we compose the reaction equation:
НCl + KOH = KCl + H2O – ion exchange reaction, potassium chloride and water are released;
1 mol 1 mol;
Let’s make calculations using the formulas of substances:
M (HCl) = 1+ 35, 5 = 36.5 mol;
M (KOH) = 39.1 + 16 + 1 = 56.1 g / mol;
Determine the number of mol of potassium hydroxide:
Y (KOH) = m / M = 33.6 / 56.1 = 0.598 mol;
Let’s make a proportion according to the equation:
0.598 mol (KOH) – X mol (HCl);
-1 mol -1 mol hence, X mol (HCl) = 0.598 * 1/1 = 0.598 mol;
Let’s calculate the volume of hydrogen chloride:
V (HCl) = 0.598 * 22.4 = 13.39 liters.
Answer: for the neutralization reaction, hydrogen chloride with a volume of 13.39 liters is required.