Calculate the volume of hydrogen fluoride formed by the interaction of 5.6 liters of hydrogen and 6 liters of fluorine.

Let’s write the reaction equation:

H2 + F2 → 2HF

Let’s find the number of moles of hydrogen:

n (H2) = V (H2) / Vm = 5.6 L / 22.4 L / mol = 0.25 mol.

Let’s find the number of moles of fluorine:

n (F2) = V (F2) / Vm = 6 L / 22.4 L / mol = 0.268 mol.

For 0.25 mol of hydrogen, 0.25 mol of fluorine is required, which means that fluorine is in excess. We are calculating the lack of (hydrogen).

Let’s find the number of moles of hydrogen fluoride:

n (HF) = 2 * n (H2) = 2 * 0.25 mol = 0.5 mol.

Let’s find the volume of hydrogen fluoride:

V (HF) = n (HF) * Vm = 0.5 mol * 22.4 L / mol = 11.2 L.

Answer: 11.2 liters.