Calculate the volume of hydrogen formed by dissolving barium in water with a chemical amount of 0.1 mol.

Here is the following reaction:
Ba + 2H2O = Ba (OH) 2 + H2.
The amount of hydrogen released during the reaction is the same as the amount of barium that entered it, 0.1 mol.
The volume of hydrogen is: 0.1 mol * 22.4 l / mol = 2.24 l.

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