Calculate the volume of hydrogen formed by the interaction of 130 g of zinc with hydrochloric acid.
September 1, 2021 | education
| Zinc metal reacts with hydrochloric (hydrochloric) acid to release hydrogen gas and form zinc chloride. The reaction is described by the following equation:
Zn + 2HCl = ZnCl2 + H2;
1 mole of zinc reacts with 2 moles of acid. In this case, 1 mol of salt is formed and 1 mol of hydrogen gas is released.
Let’s calculate the available chemical amount of zinc. To do this, divide the weight of pure metal by the weight of 1 mole of metallic zinc.
M Zn = 65 grams / mol; N Zn = 130/65 = 2 mol;
The same amount of hydrogen and zinc chloride salt will be synthesized.
Let’s calculate the volume of hydrogen. To do this, multiply the amount of substance by the volume of 1 mole of gas, which is 22.4 liters.
N H2 = 2 mol; V H2 = 2 x 22.4 = 44.8 liters;
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