Calculate the volume of hydrogen formed by the interaction of 2 mol of zinc with hydrochloric acid.

When dissolved in hydrochloric acid, metallic zinc is converted to zinc chloride. The reaction proceeds according to the following chemical reaction equation:

Zn + 2HCl = ZnCl2 + H2;

We have 2 moles of zinc.

With this amount of zinc, 2 x 2 = 4 moles of acid will react. This will synthesize 2 mol of hydrogen and 2 mol of zinc chloride. Let’s determine the volume of hydrogen. To this end, we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V H2 = 2 x 22.4 = 44.8 liters;