Calculate the volume of hydrogen formed by the interaction of 48 g of magnesium with an excess of sulfuric acid.

Magnesium interacts with sulfuric acid. In this case, magnesium sulfate is synthesized and hydrogen gas is released. This reaction is described by the following chemical reaction equation:

Mg + H2SO4 = MgSO4 + H2;

In accordance with the coefficients of the equation, upon dissolution of 1 mol of magnesium, 1 mol of gaseous hydrogen is released.

Let’s calculate the chemical amount of magnesium. To do this, divide the available weight of the metal by the weight of 1 mole of metal.

M Mg = 24 grams / mol;

N Mg = 48/24 = 2 mol;

The same amount of hydrogen will be synthesized.

We calculate its volume, for this we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters):

V H2 = 2 x 22.4 = 44.8 liters;