# Calculate the volume of hydrogen formed by the interaction of 48 g of magnesium with an excess of sulfuric acid.

January 28, 2021 | education

| Magnesium interacts with sulfuric acid. In this case, magnesium sulfate is synthesized and hydrogen gas is released. This reaction is described by the following chemical reaction equation:

Mg + H2SO4 = MgSO4 + H2;

In accordance with the coefficients of the equation, upon dissolution of 1 mol of magnesium, 1 mol of gaseous hydrogen is released.

Let’s calculate the chemical amount of magnesium. To do this, divide the available weight of the metal by the weight of 1 mole of metal.

M Mg = 24 grams / mol;

N Mg = 48/24 = 2 mol;

The same amount of hydrogen will be synthesized.

We calculate its volume, for this we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters):

V H2 = 2 x 22.4 = 44.8 liters;

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