Calculate the volume of hydrogen formed by the interaction of 5 g of technical magnesium

Calculate the volume of hydrogen formed by the interaction of 5 g of technical magnesium, containing 28% of impurities, with a solution of sulfuric acid.

Magnesium interacts with sulfuric acid. In this case, magnesium sulfate is synthesized and hydrogen gas is released. This reaction is described by the following chemical reaction equation:

Mg + H2SO4 = MgSO4 + H2;

In accordance with the coefficients of the equation, when 1 mol of magnesium is dissolved, 1 mol of gaseous hydrogen is released.

Let’s calculate the chemical amount of magnesium. To do this, divide the available weight of the metal by the weight of 1 mole of metal.

M Mg = 24 grams / mol;

N Mg = 5 x 0.72 / 24 = 0.15 mol;

The same amount of hydrogen will be synthesized.

Let’s calculate its volume, for this we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters):

V H2 = 0.15 x 22.4 = 3.36 liters;