Calculate the volume of hydrogen formed by the interaction of aluminum with 200g.

Calculate the volume of hydrogen formed by the interaction of aluminum with 200g. sulfuric acid solution in which the mass fraction of sulfuric acid is 4.9%

Metallic aluminum interacts with sulfuric acid. In this case, aluminum sulfate is formed and elemental hydrogen is released. The interaction is described by the following chemical equation.

2Al + 3H2SO4 = Al2 (SO4) 3 + 3 H2;

Let’s find the chemical amount of sulfuric acid. For this purpose, we divide its weight by the weight of 1 mole of the substance.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 200 x 0.049 / 98 = 0.1 mol;

The sulfuric acid will react to produce the same amount of hydrogen gas.

Let’s calculate its volume.

To do this, multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

V H2 = 0.1 x 22.4 = 2.24 liters;