Calculate the volume of hydrogen formed by the interaction of hydrochloric acid with zinc weighing 13 g.

For the reaction of zinc with hydrochloric acid, you need to take twice the amount of acid.

Since zinc is a divalent metal and attaches two chlorine atoms.

Zn + 2HCl → ZnCl2 + H2;

Let’s calculate the molar amount of zinc.

M Zn = 65 grams / mol;

N Zn = 13/65 = 0.2 mol;

Knowing the volume of 1 mole of an ideal gas, we calculate the volume of the same amount of hydrogen.

V H2 = 22.4 x 0.2 = 4.48 liters;