Calculate the volume of hydrogen formed by the interaction of Na (m) = 11.5 grams with hydrochloric acid.

For the solution, we write down the equation, select the coefficients:
2Na + 2HCl = 2NaCl + H2 – substitution reaction, hydrogen is released;
Let’s make calculations using the formulas of substances:
M (Na) = 22.9 g / mol;
M (H2) = 2 g / mol.
Determine the amount of sodium moles:
Y (Na) = m / M = 11.5 / 22.9 = 0.5 mol.
We make the proportion:
0.5 mol (Na) – X mol (H2);
-2 mol            – 1 mol from here, X mol (H2) = 0.5 * 1/2 = 0.25 mol.
We find the volume of hydrogen by applying Avogadro’s law:
V (H2) = 0.25 * 22.4 = 5.6 liters.
Answer: the volume of hydrogen is 5.6 liters.