Calculate the volume of hydrogen formed by the reaction of 20 g of sodium hydroxide with 14 g of silicon.

Let’s execute the solution:

In accordance with the condition of the problem, we will write the data:
2NaOH + Si + H2O = 2H2 + Na2SiO3 – OBP, hydrogen is released;

We make calculations:
M (NaOH) = 39.9 g / mol;

M (Si) = 28 g / mol;

M (H2) = 2 g / mol.

Let’s determine the amount of starting substances:
Y (NaOH) = m / M = 20 / 39.9 = 0.5 mol;

Y (H2) = 0.5 mol since the number of these compounds is equal to 2 mol.

Y (Si) = m / M = 14/28 = 0.5 mol.

We find the volume of H2:
V (H2) = 0.5 * 22.4 = 11.2 L

Answer: hydrogen produced with a volume of 11.2 liters