Calculate the volume of hydrogen generated by the interaction of 130 g of zinc with hydrochloric acid?
| November 18, 2020 | education
Zn + 2HCl = ZnCl2 + H2
M = 65g / mol Vm = 22.4 l / mol
make up the proportion and find the volume
V = 130 * 22.4 / 65 = 44.8L
Well, the answer is very simple.
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