Calculate the volume of hydrogen in which 80 g of С3Н8 evolve during dehydrogenation.

1. According to the condition of the problem, we compose the equation:
C3H8 = H2 + C3H6 – propane dehydrogenation, obtained hydrogen, propene;
2. Let’s calculate the molar masses of propane, hydrogen:
M (C3H8) = 44 g / mol;
M (H2) = 2 g / mol.
3. Determine the amount of moles of propane, if its mass is known:
Y (C3H8) = m / M = 80/44 = 1.8 mol.
According to the equation, the amount of moles of propane and hydrogen is equal to 1 mol, which means Y (H2) = 1.8 mol.
4. Find the volume of hydrogen by applying Avogadro’s law:
V (H2) = 1.8 * 22.4 = 40.32 liters.
Answer: in the process of dehydrogenation, hydrogen was released with a volume of 40.32 liters.