Calculate the volume of hydrogen obtained by reacting 14.4 g of zinc with hydrochloric acid.

univerkov | July 8, 2021 | education

We solve by analogy with the previous task:

Zn + 2HCl = ZnCl2 + H2;

n (Zn) = m (Zn): M (Zn) = 14.4 g: 65 g / mol = 0.2 mol;

n (H2) = n (Zn) = 0.2 mol;

V (H2) = n (H2) * Vm = 0.2 mol * 22.4 L = 4.48 L.

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