Calculate the volume of hydrogen obtained by reacting 48 g of magnesium with an excess of hydrochloric acid

Metallic magnesium dissolves in hydrochloric acid solution. The chemical reaction proceeds according to the following equation:

Mg + 2HCl = MgCl2 + H2 ↑;

Let’s find the chemical amount of magnesium.

To do this, we divide this weight by the weight of 1 mole of metallic magnesium.

M Mg = 24 grams / mol;

N Mg = 48/24 = 2 mol;

An equivalent amount of hydrogen gas will be synthesized.

Let’s calculate the volume of hydrogen.

For this purpose, we multiply the amount of substance by the volume of 1 mole of gas (filling volume 22.4 liters).

V H2 = 2 x 22.4 = 44.8 liters;