Calculate the volume of hydrogen obtained by reacting 48g of magnesium with excess sulfuric acid.

univerkov | March 1, 2021 | education

Given:
m (Mg) = 48 g

To find:
V (H2) -?

Decision:
1) Mg + H2SO4 => MgSO4 + H2 ↑;
2) n (Mg) = m (Mg) / M (Mg) = 48/24 = 2 mol;
3) n (H2) = n (Mg) = 2 mol;
4) V (H2) = n (H2) * Vm = 2 * 22.4 = 44.8 liters.

Answer: The volume of H2 is 44.8 liters.

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