Calculate the volume of hydrogen obtained by reacting 50 g of aluminum with sulfuric acid.

univerkov | December 10, 2020 | education

2Al + 3H2SO4 = 3H2 + Al2 (SO4) 3
amount of aluminum substance = 50/27 = 1.85 mol
n (H2) = n (al): 2 * 3 = 1.85 * 3/2 = 2.775 mol
1 mole takes 22.4 liters
2.775 – 62.16 liters of hydrogen

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