Calculate the volume of hydrogen obtained by reacting 7.2 g of zinc with hydrochloric acid.

The reaction proceeds according to the following chemical reaction equation:

Zn + 2HCl = ZnCl2 + H2;

Let’s calculate the molar amount of zinc. To do this, we divide its weight by the mass of 1 mole of the substance.

M Zn = 65 grams / mol;

N Zn = 7.2 / 65 = 0.11 mol;

With this amount of zinc, 0.11 x 2 = 0.22 mol of acid will react. This will receive 0.11 mol of hydrogen and 0.11 mol of zinc chloride. Let’s find the volume of hydrogen. To this end, we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V H2 = 0.11 x 22.4 = 2.464 liters;