Calculate the volume of hydrogen obtained by reacting zinc weighing 13 g with an excess of hydrochloric acid.

Calculate the volume of hydrogen obtained by reacting zinc weighing 13 g with an excess of hydrochloric acid. Chemical reaction equation: Zn + 2HCL = ZnCL2 + H2?

N Zn = 13/65 = 0.2 mol;

The same amount of hydrogen will be released.

Let’s define its volume.

For this purpose, we multiply the amount of the substance by the volume of 1 mole of gas (filling the space with 22.4 liters) ..

V H2 = 0.2 x 22.4 = 4.48 liters;