Calculate the volume of hydrogen obtained by reacting zinc weighing 13 g with an excess of hydrochloric acid. Chemical reaction equation: Zn + 2HCL = ZnCL2 + H2?
N Zn = 13/65 = 0.2 mol;
The same amount of hydrogen will be released.
Let’s define its volume.
For this purpose, we multiply the amount of the substance by the volume of 1 mole of gas (filling the space with 22.4 liters) ..
V H2 = 0.2 x 22.4 = 4.48 liters;
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