Calculate the volume of hydrogen produced by the reaction of 72 g of magnesium with dilute sulfuric acid.

Given: m (Mg) = 72 g;
Determine: V (H2) -?
Decision:
1. Let’s compose the reaction equation:
Mg + H2SO4 = MgSO4 + H2;
M (Mg) = 24 g / mol.
2. Determine Y (Mg) by the formula: Y = m / M;
Y (Mg) = 72/24 = 3 mol.
3. Let’s make the proportion: 3 mol Mg / 1 mol + Н2SO4 = X mol Н2 / 1 mol.
4. Y (H2) = 3 * 1/1 = 3 mol.
5.V (H2) = 22.4 * 3 = 67.2 L;
Answer: V (H2) = 67.2 liters.