The reduction reaction of iron (III) oxide is described by the following chemical equation:
2Fe2O3 + 6H2 = 4Fe + 6H2O;
To obtain 4 moles of iron, 6 moles of hydrogen are needed.
Let’s find the amount of substance in 250 grams of iron.
Its molar mass is 56 grams / mol;
N Fe = 250/56 = 4.4643 mol;
The required amount of hydrogen will be:
N H2 = 4.4643 x 6/4 = 6.6965 mol;
Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.
6.6965 mol of hydrogen will occupy the volume:
V H2 = 6.6965 x 22.4 = 150 liters;
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