Calculate the volume of hydrogen released as a result of the interaction of 45.5 g of zinc with a solution of H2SeO4.

univerkov | January 17, 2021 | education

Given:
m (Zn) = 45.5 g
To find:
V (H2)
Decision:
Zn + H2SeO4 = ZnSeO4 + H2
n (Zn) = m / M = 45.5 g / 65 g / mol = 0.7 mol
n (Zn): n (H2) = 1: 1
n (H2) = 0.7 mol
V (H2) = n * Vm = 0.7 mol * 22.4 L / mol = 15.68 L
Answer: 15.68 L

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