Calculate the volume of hydrogen released as a result of the interaction of 45.5 g of zinc with a solution of H2TeO4.

1. Let’s compose the reaction equation:

Zn + H2TeO4 = ZnTeO4 + H2 ↑;

2.Calculate the chemical amount of zinc:

n (Zn) = m (Zn): M (Zn) = 45.5: 65 = 0.7 mol;

3. Determine the amount of hydrogen:

n (H2) = n (Zn) = 0.7 mol;

4.Calculate the volume of evolved hydrogen:

V (H2) = n (H2) * Vm = 0.7 * 22.4 = 15.68 liters.

Answer: 15.68 liters.