Calculate the volume of hydrogen released as a result of the interaction of 9.75 g of zinc with a solution of H2SeO4.

1. The interaction of zinc with selenic acid occurs according to the equation:

Zn + H2SO4 = ZnSO4 + H2 ↑.

2. Find the chemical amount of zinc:

n (Zn) = m (Zn): M (Zn) = 9.75: 65 = 0.15 mol.

3. According to the reaction equation, 1 mol of zinc enters into the reaction and 1 mol of hydrogen is released, then the amount of hydrogen:

n (H2) = n (Zn) = 0.15 mol.

4. Let’s calculate the volume of hydrogen:

V (H2) = n (H2) * Vm = 0.15 * 22.4 = 3.36 liters.

Answer: 3.36 liters.