1. The interaction of zinc with selenic acid occurs according to the equation:
Zn + H2SO4 = ZnSO4 + H2 ↑.
2. Find the chemical amount of zinc:
n (Zn) = m (Zn): M (Zn) = 9.75: 65 = 0.15 mol.
3. According to the reaction equation, 1 mol of zinc enters into the reaction and 1 mol of hydrogen is released, then the amount of hydrogen:
n (H2) = n (Zn) = 0.15 mol.
4. Let’s calculate the volume of hydrogen:
V (H2) = n (H2) * Vm = 0.15 * 22.4 = 3.36 liters.
Answer: 3.36 liters.
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