Calculate the volume of hydrogen released by the action of zinc on 200 g of sulfuric acid solution

Calculate the volume of hydrogen released by the action of zinc on 200 g of sulfuric acid solution with a mass fraction of 19.6%.

Zinc metal reacts with sulfuric acid to release hydrogen gas and form zinc sulfate. The reaction is described by the following equation:

Zn + H2SO4 = ZnSO4 + H2;

1 mole of metal reacts with 1 mole of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.

Let’s calculate the amount of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 200 x 0.196 / 98 = 0.4 mol;

During the reaction, 0.4 mol of hydrogen will be synthesized. Let’s calculate its volume.

To do this, multiply the amount of substance by the volume of 1 mole of gas.

V H2 = 0.4 x 22.4 = 8.96 liters;

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