Calculate the volume of hydrogen released by the interaction of 2,3 sodium with hydrochloric acid.

The reaction of sodium with hydrochloric acid is described by the following chemical reaction equation:
2Na + 2HCl = 2NaCl + H2;
In accordance with the coefficients of the equation, the reaction of two moles of sodium leads to the formation of one mole of hydrogen.
Find the molar amount of the substance contained in 2.3 grams of sodium.
Its molar mass is 23 grams / mol.
N Na = 2.3 / 23 = 0.1 mol;
The amount of hydrogen will be:
N H2 = N Na / 2 = 0.1 / 2 = 0.05 mol;
Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.
Let’s determine the volume of 0.05 mol of hydrogen:
V H2 = 0.05 x 22.4 = 1.12 liters;